CompTIA PT0-003 Antworten & PT0-003 Zertifizierungsantworten - Photoexperienceacademy
- Name: CompTIA PenTest+ Exam
- Exam Code: PT0-003
- Certification: PT0-003
- Vendor: CompTIA
- Total Question: 630
- Price: 49$
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NEW QUESTION: 1
You administer a Microsoft SQL Server 2012 database.
Your database is experiencing deadlock issues.
You need to be able to monitor deadlocks.
Which three actions should you perform in sequence? (To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.) Select and Place:
Answer:
Explanation:
NEW QUESTION: 2
참고 :이 질문은 동일하거나 유사한 답변 선택을 사용하는 일련의 질문 중 일부입니다. 시리즈에서 둘 이상의 질문에 대한 답변 선택이 정확할 수 있습니다. 각 질문은이 시리즈의 다른 질문과 무관합니다. 질문에 제공된 정보 및 세부 사항은 해당 질문에만 적용됩니다.
Windows Server 2016을 실행하는 Server1과 Server2라는 두 서버가 있습니다. Server1과 Server2에는 Hyper-V 서버 역할이 설치되어 있습니다.
iSCSI SAN이 네트워크에 연결됩니다.
SAN에서 LUN을 생성하고 iSCSI 대상에 연결하도록 두 서버를 구성합니다.
장애 조치 클러스터를 만들고 Server1 및 Server2를 클러스터에 추가합니다. 두 서버를 iSCSI 대상에 연결하고 공유 저장소를 포맷합니다.
공유 스토리지를 클러스터에 추가해야 합니다. 솔루션은 두 노드에서 실행되는 가상 머신이 공유 스토리지에 동시에 액세스 할 수 있도록해야합니다.
어떤 도구를 사용해야 합니까?
A. 서버 관리자 앱
B. cluster.exe 명령
C. 컴퓨터 관리 스냅인
D. 디스크 관리 스냅인
E. clussvc.exe 명령
F. 장애 조치 클러스터 관리자 스냅인
G. configurehyperv.exe 명령
H. Hyper-V 관리자 스냅인
Answer: F
Explanation:
설명
참고 문헌 :
https://technet.microsoft.com/en-us/library/jj612868(v=ws.11).aspx
NEW QUESTION: 3
After the new Implementation has been performed by the Avaya Business Partner, a customer is trying to login.
While the agent is trying to login, the engineer finds the following error messages:
A. cd /var/log/Avaya/dcm/pu/UnifiedAgentControllet and tail -f ua-bpm-pu-1.log
B. cd /var/log/Avaya/dcm/pu/AuthorizationService/ and tall -fAuthorlzationService.log
C. cd /var/log/Avaya/services/AuthorizationService/ and tail -f AuthorizatlonService.log
D. cd /var/log/Avaya/dcm/pu/UnifiedAgentController and tail -f ua-ucm pu-1.log
Answer: D
NEW QUESTION: 4
You need to display the first names of all customers from the CUSTOMERS table that contain the character 'e' and have the character 'a' in the second last position.
Which query would give the required output?
A. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')IS NOT NULL ANDSUBSTR(cust_first_name, 1,-2)='a';
B. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>0 ANDSUBSTR (cust_first_name, -2, 1)='a';
C. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>'' ANDSUBSTR (cust_first_name, -2, 1)='a';
D. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>0 ANDSUBSTR (cust_first_name, LENGTH(cust_first_name),-2)='a';
Answer: B
Explanation:
Explanation/Reference:
Explanation:
The SUBSTR(string, start position, number of characters) function accepts three parameters and returns a string consisting of the number of characters extracted from the source string, beginning at the specified start position:
substr('http://www.domain.com',12,6) = domain
The position at which the first character of the returned string begins.
When position is 0 (zero), then it is treated as 1.
When position is positive, then the function counts from the beginning of string to find the first character.
When position is negative, then the function counts backward from the end of string.
substring_length
The length of the returned string. SUBSTR calculates lengths using characters as defined by the input character set. SUBSTRB uses bytes instead of characters. SUBSTRC uses Unicode complete characters.
SUBSTR2 uses UCS2 code points. SUBSTR4 uses UCS4 code points.
When you do not specify a value for this argument, then the function
The INSTR(source string, search item, [start position],[nth occurrence of search item]) function returns a number that represents the position in the source string, beginning from the given start position, where the nth occurrence of the search item begins:
instr('http://www.domain.com','.',1,2) = 18
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