2V0-31.24 Dumps PDF

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• Name: VMware Aria Automation 8.10 Professional V2
• Exam Code: 2V0-31.24
• Certification: 2V0-31.24
• Vendor: VMware
• Total Question: 630
• Price: 49$

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NEW QUESTION: 1
네트워크에 contoso.com이라는 Active Directory 도메인이 있습니다. 도메인에는 Server1이라는 구성원 서버와 DC2라는 도메인 컨트롤러가 있습니다. 모든 서버는 Windows Server 2012 R2를 실행합니다. 모든 도메인 컨트롤러는 DNS 서버로 구성됩니다.
Server1에서 서버 관리자를 열고 관리 할 다른 서버로 DC2를 추가합니다.
Server1의 서버 관리자에서 전시회에 표시된대로 DC2를 마우스 오른쪽 단추로 클릭하십시오. (전시 단추를 클릭하십시오.)

DC2를 마우스 오른쪽 단추로 클릭 할 때 DNS 관리자를 실행하는 옵션이 표시되는지 확인해야 합니다.
어떻게 해야 합니까?
A. DC2 및 Server1에서 winrmquickconfig를 실행하십시오.
B. DC2에서 기능 관리 도구를 설치하십시오.
C. 도메인에서 Server1을 DNS Admins 그룹에 추가하십시오.
D. Server1에 역할 관리 도구를 설치하십시오.
Answer: D
Explanation:
설명
DNS (Domain Name System) 역할은 이름을 숫자 인터넷 주소와 연결하는 표준 방법을 제공하는 역할입니다. 이를 통해 사용자는 일련의 숫자 대신 기억하기 쉬운 이름을 사용하여 네트워크 컴퓨터를 참조 할 수 있습니다. Windows DNS 서비스를 DHCP 서비스와 통합하면 컴퓨터가 네트워크에 추가 될 때 DNS 레코드를 추가 할 필요가 없습니다.

NEW QUESTION: 2
あなたは、Employeeという名前のクラスを作成しています。クラスははEmployeeTypeという名前の文字列プロパティを公開します。次のコードセグメントは、Employeeクラスを定義します。（行番号は参考のために含まれるだけです。）

Employeeクラス内または、Employee classに由来するクラス内のコードによるだけでEmployeeTypeプロパティ値にアクセスし、変更する必要があります。
あなたは、EmployeeTypeの資産の実現が必要条件を満たすことを確実とする必要があります。
あなたは、どの二つアクションを行うべきですか？（各正解は完全なソリューションの一部を表します。2つを選択してください。）
A. Replace line 05 with the following code segment: private get;
B. Replace line 03 with the following code segment: protected string EmployeeType
C. Replace line 06 with the following code segment: private set;
D. Replace line 06 with the following code segment: protected set;
E. Replace line 03 with the following code segment: public string EmployeeType
F. Replace line 05 with the following code segment: protected get;
Answer: B,C
Explanation:
Explanation
protected string EmpType { get; private set;}
This is a quite common way to work with properties within base classes.
Incorrect:
Not D: Cannot be used because of the internal keyword on line 03.

NEW QUESTION: 3
Which organizational theory explains the factors that promote performance of people in any organization?
A. Herzberg's theory
B. Maslow's Hierarchy theory
C. McGregor's theory
D. Expectancy theory
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Herzberg's Motivation-Hygiene Theory, also known as Two Factor Theory, was developed by Frederick Herzberg, a psychologist who found that job satisfaction and job dissatisfaction acted independently of each other. Two Factor Theory states that there are certain factors in the workplace that cause job satisfaction, while a separate set of factors cause dissatisfaction. Two Factor Theory distinguishes between the following: Motivators (e.g. challenging work, recognition, responsibility) which give positive satisfaction, arising from intrinsic conditions of the job itself, such as recognition, achievement, or personal growth. Hygiene factors (e.g. status, job security, salary and fringe benefits) which do not give positive satisfaction, although dissatisfaction results from their absence. These are extrinsic to the work itself, and include aspects, such as company policies, supervisory practices, or wages/salary. Essentially, hygiene factors are needed to ensure an employee is not dissatisfied. Motivation factors are needed in order to motivate an employee to higher performance, Herzberg also further classified our actions and how and why we do them, for example, if you perform a work-related action because you have to, then that is classed as movement, but if you perform a work-related action because you want to, then that is classed as motivation.
Incorrect Answers:
B: It describes the five layer of needs we all have.
C: McGregor's X and Y theory describes the team members and their behavior on the project and how management responds.
D: It explains the processes that an individual undergoes to make choices.

NEW QUESTION: 4



A. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
B. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
C. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo=L.CustNoWHERE D.CustNo IS NULL
D. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT(*)FROM (SELECT CustNoFROMtblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
Answer: F
Explanation:
Would list the customers with duplicates, which would equal the number of accounts.

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